3.667 \(\int x^{4/3} (a+b x)^3 \, dx\)

Optimal. Leaf size=51 \[ \frac{9}{10} a^2 b x^{10/3}+\frac{3}{7} a^3 x^{7/3}+\frac{9}{13} a b^2 x^{13/3}+\frac{3}{16} b^3 x^{16/3} \]

[Out]

(3*a^3*x^(7/3))/7 + (9*a^2*b*x^(10/3))/10 + (9*a*b^2*x^(13/3))/13 + (3*b^3*x^(16/3))/16

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Rubi [A]  time = 0.0109155, antiderivative size = 51, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 1, integrand size = 13, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.077, Rules used = {43} \[ \frac{9}{10} a^2 b x^{10/3}+\frac{3}{7} a^3 x^{7/3}+\frac{9}{13} a b^2 x^{13/3}+\frac{3}{16} b^3 x^{16/3} \]

Antiderivative was successfully verified.

[In]

Int[x^(4/3)*(a + b*x)^3,x]

[Out]

(3*a^3*x^(7/3))/7 + (9*a^2*b*x^(10/3))/10 + (9*a*b^2*x^(13/3))/13 + (3*b^3*x^(16/3))/16

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rubi steps

\begin{align*} \int x^{4/3} (a+b x)^3 \, dx &=\int \left (a^3 x^{4/3}+3 a^2 b x^{7/3}+3 a b^2 x^{10/3}+b^3 x^{13/3}\right ) \, dx\\ &=\frac{3}{7} a^3 x^{7/3}+\frac{9}{10} a^2 b x^{10/3}+\frac{9}{13} a b^2 x^{13/3}+\frac{3}{16} b^3 x^{16/3}\\ \end{align*}

Mathematica [A]  time = 0.0112979, size = 39, normalized size = 0.76 \[ \frac{3 x^{7/3} \left (2184 a^2 b x+1040 a^3+1680 a b^2 x^2+455 b^3 x^3\right )}{7280} \]

Antiderivative was successfully verified.

[In]

Integrate[x^(4/3)*(a + b*x)^3,x]

[Out]

(3*x^(7/3)*(1040*a^3 + 2184*a^2*b*x + 1680*a*b^2*x^2 + 455*b^3*x^3))/7280

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Maple [A]  time = 0.004, size = 36, normalized size = 0.7 \begin{align*}{\frac{1365\,{b}^{3}{x}^{3}+5040\,a{b}^{2}{x}^{2}+6552\,{a}^{2}bx+3120\,{a}^{3}}{7280}{x}^{{\frac{7}{3}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^(4/3)*(b*x+a)^3,x)

[Out]

3/7280*x^(7/3)*(455*b^3*x^3+1680*a*b^2*x^2+2184*a^2*b*x+1040*a^3)

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Maxima [A]  time = 1.4617, size = 47, normalized size = 0.92 \begin{align*} \frac{3}{16} \, b^{3} x^{\frac{16}{3}} + \frac{9}{13} \, a b^{2} x^{\frac{13}{3}} + \frac{9}{10} \, a^{2} b x^{\frac{10}{3}} + \frac{3}{7} \, a^{3} x^{\frac{7}{3}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(4/3)*(b*x+a)^3,x, algorithm="maxima")

[Out]

3/16*b^3*x^(16/3) + 9/13*a*b^2*x^(13/3) + 9/10*a^2*b*x^(10/3) + 3/7*a^3*x^(7/3)

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Fricas [A]  time = 1.47577, size = 107, normalized size = 2.1 \begin{align*} \frac{3}{7280} \,{\left (455 \, b^{3} x^{5} + 1680 \, a b^{2} x^{4} + 2184 \, a^{2} b x^{3} + 1040 \, a^{3} x^{2}\right )} x^{\frac{1}{3}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(4/3)*(b*x+a)^3,x, algorithm="fricas")

[Out]

3/7280*(455*b^3*x^5 + 1680*a*b^2*x^4 + 2184*a^2*b*x^3 + 1040*a^3*x^2)*x^(1/3)

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Sympy [A]  time = 5.23708, size = 49, normalized size = 0.96 \begin{align*} \frac{3 a^{3} x^{\frac{7}{3}}}{7} + \frac{9 a^{2} b x^{\frac{10}{3}}}{10} + \frac{9 a b^{2} x^{\frac{13}{3}}}{13} + \frac{3 b^{3} x^{\frac{16}{3}}}{16} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**(4/3)*(b*x+a)**3,x)

[Out]

3*a**3*x**(7/3)/7 + 9*a**2*b*x**(10/3)/10 + 9*a*b**2*x**(13/3)/13 + 3*b**3*x**(16/3)/16

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Giac [A]  time = 1.05051, size = 47, normalized size = 0.92 \begin{align*} \frac{3}{16} \, b^{3} x^{\frac{16}{3}} + \frac{9}{13} \, a b^{2} x^{\frac{13}{3}} + \frac{9}{10} \, a^{2} b x^{\frac{10}{3}} + \frac{3}{7} \, a^{3} x^{\frac{7}{3}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(4/3)*(b*x+a)^3,x, algorithm="giac")

[Out]

3/16*b^3*x^(16/3) + 9/13*a*b^2*x^(13/3) + 9/10*a^2*b*x^(10/3) + 3/7*a^3*x^(7/3)